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2x^2+2x=7x-12
We move all terms to the left:
2x^2+2x-(7x-12)=0
We get rid of parentheses
2x^2+2x-7x+12=0
We add all the numbers together, and all the variables
2x^2-5x+12=0
a = 2; b = -5; c = +12;
Δ = b2-4ac
Δ = -52-4·2·12
Δ = -71
Delta is less than zero, so there is no solution for the equation
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